Engineering Very basic circuits 1 question. Charge and current

AI Thread Summary
The discussion revolves around calculating the charge q(t) from the given current function, 20 cos(10t + π/6)μA, with an initial charge q(0) = 2 μC. The user initially misinterpreted the integration of the current, leading to confusion over the correct final expression for q(t). The solutions manual provides the answer as (2sin(10t + π/6) + 1)μC, which the user initially thought should include +2 instead of +1. Clarification came when it was pointed out that the entire function represents q(t), not just the added initial charge. Ultimately, the user understood the correct interpretation of the solution.
A.J.710
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Homework Statement


Find the charge q(t) flowing through a device if the current is: 20 cos(10t + π/6)μA, q(0) = 2 μC

Homework Equations


∫ i(t)dt +q(0)

The Attempt at a Solution


I am studying for a test by working all the problems I can and then looking at the solutions manual. The solutions manual says the answer is (2sin(10t+π/6)+1)μC. I got the same thing except +2 at the end since q(0) is 2. It's really bugging me that I can't figure out why. Can anyone please explain?
 
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A.J.710 said:
The solutions manual says the answer is (2sin(10t+π/6)+1)μC. I got the same thing except +2 at the end since q(0) is 2.
If you plug in t = 0 to your solution and the manual's, which one gives the correct answer?
 
Doc Al said:
If you plug in t = 0 to your solution and the manual's, which one gives the correct answer?
Ahh, got it now. Thank you. I didn't realize that's what it meant. I was just adding the q(0) but I didn't realize until you pointed it out that the entire function in itself is q.
 

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