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Voltage drops in circuits

  1. Feb 8, 2009 #1
    1. The problem statement, all variables and given/known data
    Assume the wire resistance is 1.0 Ohms, the power supply is an ideal 6V voltage source, and the light bulb resistance is 30 Ohms.
    In the circuit below:
    a). A lightbulb is connected to the power supply using two such wires. Calculate the current (in A) in the circuit.
    b) Calculate the voltage drop (in V) across each wire.

    2.jpg

    2. Relevant equations
    V=IR
    R=dL/A


    3. The attempt at a solution
    a.) I = 6/1 = 6ohms
    b.) V = 6 x 1 = 6V

    I have no clue how to do this problem. Professor hasn't taught this material yet.

    Thanks
     
  2. jcsd
  3. Feb 8, 2009 #2

    rock.freak667

    User Avatar
    Homework Helper

    If the light bulb is connected with the two wires. Then the resistances are in series.
    Find the total resistance. The total pd=6V.
    So the total current is simply I=V/R.

    The sum of the voltage drops across the wires and bulb will add up to be 6. So just use V=IR and you'll get it.
     
  4. Feb 8, 2009 #3
    Consider this circuit as an ideal voltage source connected in series with 3 resistances (wire segment, light bulb, wire segment). Maybe redrawing the circuit will help. Ask yourself what the total resistance of the circuit is, and how this relates to the current. Then ask yourself how this current relates to the voltage drops across each individual element.
     
  5. Feb 8, 2009 #4
    So for a.) I = 6/32 => 0.19 Amps

    b.)V = 0.19 x 32 => 6 volts ?
     
  6. Feb 8, 2009 #5
    a) is correct. For b) think of the individual wire elements. From the picture, it looks like each wire would have a resistance of 0.5 ohms. 6 volts is the drop in potential across the total resistance.
     
  7. Feb 8, 2009 #6
    I see what you meant by the total resistance. Shouldn't each wire have a resistance of 1 ohm and not 0.5? From part a 2 ohms for the wires and 30 for the bulb
     
  8. Feb 8, 2009 #7
    Yes, you're right, each piece of wire is 1 ohm. I thought it was referring to the wire as a whole, and wanted you to divide the total wire resistance by 2 in order to split it up. Sorry for the confusion :/

    Now for part b) you need to find the voltage drop across each piece of wire. You have the current through each piece, and you know the resistance of each piece.
     
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