Volume of a Cylinder: Find via Polar Graphs

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Homework Statement


Find the volume of solid bounded below by plane z = 0 , and above by z = 10 , sides by (x^2) + (y-1)^2 = 1 ..

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The Attempt at a Solution


I fins the area of the base first , which is pi (1^2) = pi , then i integrate with the length , which is from z = 0 to z=6 . so , my ans is 6pi , is my ans correct ?

But ,the author used cylindrical coordinate (polar graph method) , from r = 0 to r = 2sin theta , because the base of cylinder is centered at (0,1 )
 
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Your problem statement says the cylinder lies between the planes z = 0 and z = 10, but your attempt at a solution uses only the interval from z = 0 to z = 6. Which one is correct?
 
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slider142 said:
Your problem statement says the cylinder lies between the planes z = 0 and z = 10, but your attempt at a solution uses only the interval from z = 0 to z = 6. Which one is correct?
typo ,
I fins the area of the base first , which is pi (1^2) = pi , then i integrate with the length , which is from z = 0 to z=10 . so , my ans is 10pi , is my ans correct ?

But ,the author used cylindrical coordinate (polar graph method) , from r = 0 to r = 2sin theta , because the base of cylinder is centered at (0,1 )
 
That's fine. Your method is correct, and so is the author's. :-) I tend to prefer your method because its simpler. The author's intent is probably for you to compare the classical method to integration and see that they yield equivalent volumes for the classical solids.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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