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Water Pressure Velocity Acceleration (dv/dt)

  1. Mar 30, 2012 #1
    I am having trouble solving this problem. Any assistance is greatly appreciated.

    Water is discharged from a pipeline at a velocity of v given by v=1192p^(1/2), where p is the pressure (in psi). If the water pressure is changing at a rate of 404 psi/second, find the acceleration (dv/dt) of the water when p = 34 psi.

    I have soved the v' to equal: 596p^(-.5).
    Does dv/dt = 596^(-.5)/t for (dv/dt)?
    What's the next step?
  2. jcsd
  3. Mar 30, 2012 #2


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    Welcome to PF!

    Hi! Steve Welcome to PF! :smile:

    Use the chain rule :wink:
  4. Mar 31, 2012 #3
    Thanks Tniy-Tim!
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