I am having trouble solving this problem. Any assistance is greatly appreciated. Water is discharged from a pipeline at a velocity of v given by v=1192p^(1/2), where p is the pressure (in psi). If the water pressure is changing at a rate of 404 psi/second, find the acceleration (dv/dt) of the water when p = 34 psi. I have soved the v' to equal: 596p^(-.5). Does dv/dt = 596^(-.5)/t for (dv/dt)? What's the next step?