- #1
Steve Page
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I am having trouble solving this problem. Any assistance is greatly appreciated.
Water is discharged from a pipeline at a velocity of v given by v=1192p^(1/2), where p is the pressure (in psi). If the water pressure is changing at a rate of 404 psi/second, find the acceleration (dv/dt) of the water when p = 34 psi.
I have soved the v' to equal: 596p^(-.5).
Does dv/dt = 596^(-.5)/t for (dv/dt)?
What's the next step?
Water is discharged from a pipeline at a velocity of v given by v=1192p^(1/2), where p is the pressure (in psi). If the water pressure is changing at a rate of 404 psi/second, find the acceleration (dv/dt) of the water when p = 34 psi.
I have soved the v' to equal: 596p^(-.5).
Does dv/dt = 596^(-.5)/t for (dv/dt)?
What's the next step?
