Hi; Could someone please help me with the following question: In a double-slit experiment it is found that blue light of wavelength 460 nm gives a second-order maximum at a certain location on the screen. What wavelength of visible light would have a minimum at the same location? Can i use the equation dsin(theta) = m(lamda)? If I use this, i plug in the answer I get for dsin(theta) into this equation: dsin(theta) = (M+0.5)(lamda)? Is this right, because it doesn't work. Thanks for your help.(adsbygoogle = window.adsbygoogle || []).push({});

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# Waves- Interference/Double-slit experiment

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