Waves & Sound: Combine Pressure & Density to Produce Dimensions of Speed

AI Thread Summary
The discussion focuses on how to combine pressure and density to derive the speed of sound in air. Participants analyze the fundamental dimensions of pressure and density, ultimately concluding that the speed of sound can be expressed as the square root of the ratio of pressure to density, represented mathematically as √(P/ρ). The conversation highlights the analogy between pressure and tension in wave equations, emphasizing that while they cannot be equated, they can be combined to yield dimensions of speed. The final agreement confirms that this approach is valid and insightful for understanding sound as a wave phenomenon. The analysis effectively clarifies the relationship between these physical quantities.
sammmy
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Homework Statement


Two important quantities associated with air are the pressure and density. How can the pressure and density be combined to produce dimensions of speed? Look up the pressure and density of air at sea level and use your equation to estimate the speed of sound. Is your answer reasonable?

Homework Equations


pressure (P)= force/area
area of sphere= 4\Pid^{2}
density (p)= mass/volume

The Attempt at a Solution


somehow I'm assuming you're supposed to use the equation for the speed of a wave that includes force, which is V=\sqrt{T/\mu}
but T=tension of the string. Since sound is not a wave on a string.. i am thoroughly confused.
 
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Welcome to PF sammmy!

I think the first thing would be to write out the fundamental dimensions of each quantity:

I'll use [L] to mean "length", [M] for mass, and [T] for time:

[P] = \frac{[F]}{[A]} = \left([M] \cdot \frac{[L]}{[T]^2}\right)\left(\frac{1}{[L]^2}\right)

in the last part on the right hand side, the quantity in the first set of parentheses is force (mass*acceleration), and the quantity in the second set of parentheses is 1/area.

So, pressure reduces to dimensions of:

[P] = \frac{[M]}{[L][T]^2}

similarly for density:

[\rho] = \frac{[M]}{[V]} = \frac{[M]}{[L]^3}

Now, does anything jump out at you? Hint: you want to get rid of [M] entirely.
 
Well, since dimensions of speed are meters/second- It seems as if the density equation would need to be flipped to 1/\rho which is equal to L^{3}/M so the masses cancel out

but I'm not sure how you can equate pressure and density.. ?
 
sammmy said:
Well, since dimensions of speed are meters/second- It seems as if the density equation would need to be flipped to 1/\rho which is equal to L^{3}/M so the masses cancel out

but I'm not sure how you can equate pressure and density.. ?

You can't "equate" them. But you can combine them together algebraically in an expression, in such a way that you are left with something that has dimensions of [L]/[T] (speed).
 
how about..
\sqrt{P/\rho} so that \sqrt{(M/LT^{2})/(M/L^{3})} which equals L/T
 
sammmy said:
how about..
\sqrt{P/\rho} so that \sqrt{(M/LT^{2})/(M/L^{3})} which equals L/T

Yes. Good work.

EDIT: Sound is indeed a wave, and you could have derived this result from the appropriate wave equation. I bring this up because your attempt in your original post to make an analogy with the wave speed for waves propagating in a string was a good insight. P is sort of analogous to T in its role of "forcing" or driving the oscillations (I think). The mass density appears in both equations and is a sort of "inertial" factor.
 
cepheid said:
yes. Good work.

Edit: Sound is indeed a wave, and you could have derived this result from the appropriate wave equation. I bring this up because your attempt in your original post to make an analogy with the wave speed for waves propagating in a string was a good insight. P is sort of analogous to t in its role of "forcing" or driving the oscillations (i think). The mass density appears in both equations and is a sort of "inertial" factor.

thank you!
 
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