What Altitude Should a Geosynchronous Satellite Orbit Mars?

AI Thread Summary
A geosynchronous satellite for Mars must maintain an orbit that matches the planet's rotation period of 24.6229 hours. To determine the correct altitude, the gravitational force must be equated to the centripetal force, using the formula F = GmM1/R^2. The initial attempt at calculating the radius involved the equation r = (GMT/2pi)^0.5, but further clarification and calculations are necessary to ensure accuracy. Participants in the discussion emphasize the importance of showing detailed work to identify any mathematical errors. Ultimately, the goal is to find the precise altitude for effective communication from the satellite.
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Homework Statement



In the not-too-distant future astronauts will travel to Mars to carry out scientific explorations. As part of their mission, it is likely that a "geosynchronous" satelite will be placed
above a given point on the Martian equator to facilitate communcations. At what altitude above the surface of Mars should such a satellite orbit? (the Martian day is 24.6229 hours. other relevant information can be found in appendix c.) At what altitude above the suface of Mars should such a satellite orbit?

Homework Equations

I know that we should use Universal Gravitation (F = GmM1/R^2).

The Attempt at a Solution



r = (GMT/2pi)^.5
i did this to solve for the radius, converting the Maritan day into seconds first.
 
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Hello yiyi,

Welcome to Physics Forums! :smile:

yiyi said:

Homework Statement



In the not-too-distant future astronauts will travel to Mars to carry out scientific explorations. As part of their mission, it is likely that a "geosynchronous" satelite will be placed
above a given point on the Martian equator to facilitate communcations. At what altitude above the surface of Mars should such a satellite orbit? (the Martian day is 24.6229 hours. other relevant information can be found in appendix c.) At what altitude above the suface of Mars should such a satellite orbit?

Homework Equations




I know that we should use Universal Gravitation (F = GmM1/R^2).

The Attempt at a Solution



r = (GMT/2pi)^.5
i did this to solve for the radius, converting the Maritan day into seconds first.

You will have to show more work. Something isn't quite right to me with your "r = (GMT/2pi)^.5" answer. Perhaps if you show some of your work we can help find what went wrong.

As a hint though, set the gravitational force equal to the centripetal force and solve for r.
 
I think I just did some mathematical calculations wrong. Thanks for the help!
 
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