What Angle Causes the Fishing Line to Break with a 1.95 kg Ball?

  • Thread starter Thread starter finlejb
  • Start date Start date
  • Tags Tags
    Pendulum Tension
AI Thread Summary
The discussion centers on determining the angle at which a fishing line will break when a 1.95 kg ball is released from rest, with the line taut and horizontal. The equation T = mg(3-2cosθ) is proposed to calculate the tension in the line, but users are struggling to solve for the angle θ correctly. Participants highlight that the ball's motion involves both gravitational force and centripetal acceleration as it moves in a circular arc. The conversation emphasizes the need to consider all forces acting on the ball, not just gravity, to accurately find the breaking angle. Understanding these dynamics is crucial for solving the problem effectively.
finlejb
Messages
14
Reaction score
0
A 1.95 kg ball is attached to the bottom end of a length of 11.0 lb (48.9 N) fishing line. The top end of the fishing line is held stationary. The ball is released from rest while the line is taut and horizontal At what angle (measured from the vertical) will the fish line break?

I've got the equation T = mg(3-2cos\theta) but when I solve that for \theta with T = 48.9, it says it's wrong. any thoughts?
 
Physics news on Phys.org
finlejb said:
I've got the equation T = mg(3-2cos\theta)
Show how you arrived at that equation.
 
finlejb said:
A 1.95 kg ball is attached to the bottom end of a length of 11.0 lb (48.9 N) fishing line. The top end of the fishing line is held stationary. The ball is released from rest while the line is taut and horizontal At what angle (measured from the vertical) will the fish line break?

I've got the equation T = mg(3-2cos\theta) but when I solve that for \theta with T = 48.9, it says it's wrong. any thoughts?
What is the acceleration of the ball as it moves in this path? What does it depend on? What provides this acceleration? Hint: it is not just gravity that provides the acceleration here.

AM
 
Andrew, I don't see any other source of acceleration. Explain.
 
hsiao said:
Andrew, I don't see any other source of acceleration. Explain.
The ball is falling (gravity) and it is moving in a circular arc.

AM
 
hsiao said:
Andrew, I don't see any other source of acceleration. Explain.
The ball is attached to a fishing line.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is（Figure 2）： F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Work done on a conical pendulum
Replies
3
Views
2K
What Angle Causes the Fishline to Break?
Replies
6
Views
2K
Foucault Pendulum at the North Pole
Replies
9
Views
2K
What is the correct tension equation for a pendulum at rest?
Replies
2
Views
2K
Conservation of Energy Ball Problem
Replies
1
Views
3K
Differential Equation for a Pendulum
Replies
21
Views
2K
Pendulum String Breaking Point Problem
Replies
1
Views
6K
Is the Angular Momentum of a Pendulum Conserved?
Replies
5
Views
6K
Finding Tension force in a SHM Pendulum
Replies
4
Views
2K
What angle will the vine break and what's the max tension?
Replies
4
Views
2K

Hot Threads

Recent Insights

Back
Top