What Are the Implications of Parity Operations and CPT Theorem?

physicsforumsfan
Messages
28
Reaction score
0
Hey all,

I have a four part question:

Homework Statement



Let ψ represent a wave function where x,y,z are spatial coordinates and t is time. The particles \pi^{-}, \pi^{0}, \pi^{+} are pions (\pi mesons). The parity inversion operation is represented by

The Attempt at a Solution



Parities involve a simple change in sign with regards to the components.

∴Pψ(x,y,z,t)=ψ(-x.-y,-z,-t)

Part B

Homework Statement



The time reversal of above qs is represent by?

The Attempt at a Solution



I am not sure if this is inversion of the components (xyzt) or inverting the sign of the pi mesons. My answer is but not sure:

Tψ(x,y,z,t)=ψ(-x.-y,-z,t)

Part C

Homework Statement



For first question, charge conjugation is what?

The Attempt at a Solution



C\pi^{-} = \pi^{+}, C\pi^{+}=\pi^{-}, C\pi^{0} = \pi^{0}

This seems straight forward but maybe too straight forward?

Part D

Homework Statement



According to the CPT theorem, if P is violated in an experiment and T is not, then we know what?

The Attempt at a Solution



Since CP are always grouped, the answer would be:

C is also violated?

Help anyone,

Thanks
 
Physics news on Phys.org
Hi,

no reply?

Help?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...

Similar threads

Back
Top