What are the limits for a double polar integral in the first quadrant?

BananaMan
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i have the integral \int_{0}^{\infty} \int_{0}^{\infty} (-x^2-y^2) \ dx dy
(double integral with both limits the same...assuming my first bash at the tex comes out

it says to transfer it into polar form and evaluate it

i have no idea how to convert a limit of infinity to polar form, help please
 
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Really? Your instructor has given you this problem without the slightest indication of what polar coordinates are? What an evil person! And you textbook doesn't have anything about the "differential of area" in polar coordinates?? Are you sure you are reading it correctly?
 
no, we have gone over polar co-ordinates, but never with an integration limit of infinity so i have no idea how to convert the limit to evaluate it
 
Make a skech of the integration area for x and y.
How can you cover the same area in polar coördinates?
 
how do you sketch the area of x or y to infinity though?
 
Are you serious? x going from 0 to \infty[/tex] and y going from 0 to \infty means that x and y may take on all non-negative values- the first quadrant. Now, what do r and \theta range over in the first quadrant?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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