What are the Second Partials in the Multivariable Chain Rule?

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This is a stupid question but...

The regular multivariable chain rule is:

u_x = u_v v_x + u_w w_x and u_y = u_v v_y + u_w w_y where u(v(x, y), w(x, y))

Now, are there formulae for the second partials u_{xx}, u_{xy}, u_{yy}

I just want to check myself (this isn't a homework problem, though it is study for a class) Thanks
 
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Easy, just use product rule:

u_{xx} = (u_x)_x = (u_vv_x + u_ww_x)_x = u_{vx}v_x + u_vv_{xx} + u_{wx}w_x + u_ww_{xx}
 
AKG said:
Easy, just use product rule:

u_{xx} = (u_x)_x = (u_vv_x + u_ww_x)_x = u_{vx}v_x + u_vv_{xx} + u_{wx}w_x + u_ww_{xx}

If I recall correctly though, u_{vx} is really u_{vv}v_x + u_{vw}w_x
 
Yeah, it probably is.
 
Hmm, yeah. I knew it was straightforward, but it seemed too simple for some reason.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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