What Factors Determine the Maximum Allowable Force on a Wooden Beam?

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The discussion centers on determining the maximum allowable force on a wooden beam before failure, using the relationship between shear and normal stress. Participants clarify the resolution of force P into components along and normal to the beam's end, applying the factor of safety based on given failure stresses. There is confusion regarding the role of distance b in the calculations, with questions about the correct resolution of P into shear and normal forces. The conversation emphasizes the need to correctly apply trigonometric functions to the force components, specifically addressing the potential need for dividing by 2. Understanding these calculations is crucial for accurately determining the maximum allowable force on the beam.
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Homework Statement


Finding the maximum allowable force P before failure

Homework Equations


Shear /normal stress = Force / Area

The Attempt at a Solution


I know that I can resolve the force P to be along and normal to the end of the wooden beam to find the respective forces separately,applying factor of safety, from the failure stresses given and therefore, determine which P is lower which shall be the maximum allowable P. However, I do not see there the distance b come into play. Am i missing something?
 

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Can you show how you "resolved" P?
 
Pcos30 will be my shear force and Psin30 will be my normal force to the end of the beam.
 
Don't you mean P/2cos30 and P/2sin30?
 

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