What Force Accelerates a Sled on Snowy Ground?

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To determine the force needed to accelerate a sled of mass 13.4 kg at 2.69 m/s² on snowy ground, both the applied force and the frictional force must be considered. The user calculated the force from acceleration alone as 36.046 N, but this does not account for the frictional force opposing the motion. The kinetic friction force, calculated using the kinetic friction coefficient of 0.111, must be added to the force required for acceleration to find the total force needed. A free body diagram can help visualize the forces acting on the sled, ensuring all forces are accounted for in the final calculation. Understanding these dynamics is crucial for solving the problem correctly.
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Homework Statement


A sled of mass 13.4 kilograms is pulled along flat snow-covered ground. The static friction coefficient is 0.334, and the kinetic friction coefficient is 0.111.
I solved both part a and b, but I am having trouble with part c.
c. Once moving, what force is needed to accelerate the sled 2.69 meters per second per second?



Homework Equations


am=f
u=f/n


The Attempt at a Solution



Im confused on how to do this.
So Its asking for the force pushing the sled forward. Using the formula am=f
if i plug in acceleration and the mass i get 13.4x2.69=36.046, but it said it was wrong.
Am I missing something? Do I need to factor in frictional force?
Would I add 14.6 to 36.046? 14.6 is the force needed to push the object at a constant velocity.
 
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mmoran said:

Homework Statement


A sled of mass 13.4 kilograms is pulled along flat snow-covered ground. The static friction coefficient is 0.334, and the kinetic friction coefficient is 0.111.
I solved both part a and b, but I am having trouble with part c.
c. Once moving, what force is needed to accelerate the sled 2.69 meters per second per second?



Homework Equations


am=f
u=f/n


The Attempt at a Solution



Im confused on how to do this.
So Its asking for the force pushing the sled forward. Using the formula am=f
if i plug in acceleration and the mass i get 13.4x2.69=36.046, but it said it was wrong.
Am I missing something? Do I need to factor in frictional force?
Would I add 14.6 to 36.046? 14.6 is the force needed to push the object at a constant velocity.

Do a freebody diagram of the accelerating sleigh. What are the forces acting on the sleigh? What do they necessarily sum to?

AM
 
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