What Forces Act on Three Blocks on a Frictionless Surface?

  • Thread starter Thread starter ScullyX51
  • Start date Start date
  • Tags Tags
    Blocks Tension
AI Thread Summary
Three identical blocks are connected by strings and pulled on a frictionless surface by a force F. The tension between blocks B and C is given as T = 3.00 N, with each block having a mass of 0.400 kg. The acceleration of the system can be calculated using F = ma, leading to the conclusion that the total force F is distributed among the blocks. The tensions between the blocks can be derived from the overall force and the required acceleration, with T:AB being 2/3 of F and T:BC being 1/3 of F. The initial calculations for tension and acceleration were incorrect, indicating a need to reassess the force distribution among the blocks.
ScullyX51
Messages
35
Reaction score
0

Homework Statement


Three identical blocks connected by ideal strings are being pulled along a horizontal frictionless surface by a horizontal force F_vec. (Intro 1 figure) The magnitude of the tension in the string between blocks B and C is T = 3.00 N. Assume that each block has mass m = 0.400 kg

What is the magnitude F of the force?
What is the tension T:AB in the string between block A and block B?


Homework Equations


F=ma



The Attempt at a Solution


I am unsure of how to approach the first part of the problem. For the second part, since t is the only force acting this the block,
I have: T=ma
I solve for A from the first part of the equation where t is given as follows:
t=ma
3=.400a
a=3/.4
a=7.5 m/s^2

I plugged this into to solve for the other tension as follows:
t=ma
t=.4*7.5
t=3

Mastering physics is saying the tension and the acceleration is wrong. Where did I screw up?
 
Physics news on Phys.org
What is the order of your blocks?

T <---{A}--{B}--{C}

Generally, whatever your force is, the acceleration will be F/(3*m) and then the intermediate tensions would be whatever force is needed to keep the blocks remaining moving with that acceleration.

In the example above that would be 2/3*F between A:B and 1/3*F between B:C
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top