What is a differential equation?

AI Thread Summary
A differential equation describes the motion of a skier of mass M on a frictionless hill at an angle θ, starting from rest and experiencing a velocity-dependent drag force F = -bv. The equation can be derived using Newton's second law, resulting in m(d²s/dt²) = mg sin(θ) - b(ds/dt). Understanding differential equations requires calculus, and their solutions can be complex, often necessitating specific techniques. The discussion emphasizes the importance of expressing answers in terms of M, b, θ, and fundamental constants. Mastery of these concepts is essential for solving physics problems involving motion and forces.
KAV
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Homework Statement



A skier of mass M is skiing down a frictionless hill that makes an angle θ with the horizontal. The skier starts from rest at time t = 0 and is subject to a velocity-dependent drag force due to air resistance of the form F = -bv, where v is the velocity of the skier and b is a positive constant. Express all algebraic answers in terms of M, b, θ , and fundamental constants.

Write a differential equation that can be used to solve for the velocity of the skier as a function of time.

Homework Equations



I understand a differential equation involves calculus, but I don't know how to apply it.

The Attempt at a Solution



v = (mgsinθ - ma)/b
 
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Try finding the resultant force, then use Newton's 2nd law with non-constant velocity, i.e. F=m \frac{dv}{dt}
 
KAV said:

Homework Statement



A skier of mass M is skiing down a frictionless hill that makes an angle θ with the horizontal. The skier starts from rest at time t = 0 and is subject to a velocity-dependent drag force due to air resistance of the form F = -bv, where v is the velocity of the skier and b is a positive constant. Express all algebraic answers in terms of M, b, θ , and fundamental constants.

Write a differential equation that can be used to solve for the velocity of the skier as a function of time.

Homework Equations



I understand a differential equation involves calculus, but I don't know how to apply it.

The Attempt at a Solution



v = (mgsinθ - ma)/b
You have written the correct differential equation already. In differential form it would be:

m\frac{d^2s}{dt^2} = mgsin\theta - b\frac{ds}{dt}

A differential equation is just an equation containing differentials. The solution of these equations is often complicated. Certain techniques for solving them exist and are the subject of a course in differential equations.

AM
 
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