What is the angular momentum of an electron

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The discussion focuses on calculating the angular momentum of an electron in the n = 13 level of the Bohr hydrogen atom using the formula L = nħ, where ħ is the reduced Planck's constant. The user initially attempted to use the equation L = mr²ω and derived the radius with r = n²a, but faced difficulties in obtaining the correct angular momentum value. It was clarified that in the Bohr model, angular momentum is quantized and can be zero for an electron in an s state, which may cause confusion. The correct approach emphasizes the quantization of angular momentum rather than classical mechanics. Understanding these principles is essential for accurately determining angular momentum in quantum systems.
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What is the angular momentum of an electron in a level with n = 13 in the Bohr hydrogen atom (Planck's constant: h = 6.63 10-34 J s)?

I used the equation L= mr2ω
L=nh/2pi

I solved for r:
r = n2a where a=5.29•10-11 m

plugging all these values in, i can't seem to get the right answer for angular momentum. Also what are the units for angular momentum?
 
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Gack! Angular momentum is r x p. r is meters, p is kg*m/sec. But an electron can be in level n=13 with zero angular momentum if it's in an s state. I don't get the question.
 
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He said bohr model, and in that model you don't have s,p,d waves etc.

but instead, L is quantized as: L = n*hbar

So that is basically what you need dude
 
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