What is the Average Net Force on a Diver During a Fall into a Swimming Pool?

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To find the average net force on a diver falling into a swimming pool, one must first calculate the diver's final velocity just before hitting the water using the equation Vf^2 = Vi^2 + 2ad. Once the final velocity is established, it can be used as the initial velocity in the equation Vf = Vi + at to determine the acceleration during the diver's time in the water. The net force acting on the diver can then be calculated by considering the upward buoyant force and the downward gravitational force (mg), leading to the equation: upward force - mg = ma. This approach emphasizes the importance of understanding the forces at play and applying the correct kinematic equations to solve the problem. The discussion highlights the need for clarity in applying physics formulas to arrive at the solution effectively.
Naldo6
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1. Homework Statement [/b]

A 76.0 kg diver falls from rest into a swimming pool from a height of 6.9 m. It takes 1.44 s for the diver to stop after entering the water. Find the magnitude of the average net force exerted on the diver during that time.
 
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What equations do you know of that would be relevant to this problem? Where are you getting stuck at in trying to solve this problem?
 
idont know how to do it.. i just know that F= J/delta t...but i don't know anymore ...or i don't know if this proble is solved by other way or other formula...
 
wouldn't the only force be gravity?
 
i don't know... byt F= J/delta t
and J=delta P= (mass)( velocity - 0)
and i don't know if the 1.44 s is the right delta t to the formula...

also i need to calculate that velocity because the mass is 76.0 kg
 
After rereading the problem, wouldn't you need to find the bouyent force and then subtract the mg from it? Because those are the only two force I see working on the diver.
 
and how i do that?... please explian me better...
 
sorry, I don't remember the formula, but there is another way I think.

It's rather long.

You know the formula F=ma right?

The diver has an upward force pushing it up until it stops and a downward force.
The downward force is mg. To find the upward force:

upwardforce - mg = ma

because the mg is smaller (that's why it stops) we the upward force (winner) from the downwardforce (loser)

but you don't know a, but you could find it.

first, figure out the final velocity of the diver RIGHT BEFORE he hits the water. This can be found by using a distance formula. Vf^2 = Vi^2 + 2ad.

That final velocity becomes the intial velocity once the diver is in the water. So use another formula, Vf = Vi + at, and solve for a.

Finally, go back to the top and plug in a.

*The net force should be the upward force - the downward force* because net force is by how much a force is winning

I hope this right. I am not too sure, but this looks like the best way to solve the problem.
 
thanks i did it...
 

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