What is the change in entropy of the gas?

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The change in entropy for one mole of an ideal gas expanding isothermally from a volume of 1x10^3 cm³ to 2x10^3 cm³ can be calculated using the formula ΔS = Q/T. In this case, the heat capacity relationships, ΔS = nC_Pln(V_2/V_1) + nC_Vln(P_2/P_1), are applicable. Since the process is isothermal, the change in internal energy (ΔU) is zero, simplifying the calculations. The gas remains in contact with a heat reservoir, ensuring constant temperature throughout the expansion. Thus, the entropy change can be determined without needing the temperature value directly.
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One mole of an ideal gas in a cylinder fitted with a piston is made to expand slowly (reversible) from an initial volume of 1x10^3 cm3 to a final volume of 2x10^3 cm3. The cylinder is in contact with a heat reservoir so that, throughout the expansion process, the gas is held at a constant temperature. What is the change in entropy of the gas?
 
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isothermal process

For an isothermal process, \Delta S = Q/T.
 
This problem can be solved using

\Delta S = nC_Pln\frac{V_2}{V_1}+nC_Vln\frac{P_2}{P_1}

All you need to do now, is to recall the relationship between an ideal gas and the heat capacity. You don't need the temperature to solve this problem.
 
Along with Doc's equation, you'll want to use \Delta U = Q + W[/tex]
 
but for isothermal process change in internal energy(delta U) is equal to 0.
 
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