What is the coefficient of kinetic friction for a wood block on a spring?

AI Thread Summary
The discussion revolves around calculating the coefficient of kinetic friction for a wood block attached to a spring. The block has a mass of 0.570 kg and a spring constant of 180 N/m, with the spring compressed by 4.4 cm and then stretched 1.7 cm beyond equilibrium. The main equation proposed for the coefficient of kinetic friction (uk) is derived from the balance of forces involving gravitational force and spring force. Additionally, energy considerations are introduced, suggesting that the energy stored in the spring relates to the work done against friction. The final solution was reached after clarifying the relevant equations and concepts.
RileyAllen
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Homework Statement


A 0.570-{\rm kg} wood block is firmly attached to a very light horizontal spring(k=180 N/m). It is noted that the block-spring system, when compressed 4.4 cm and released, stretches out 1.7 cm beyond the equilibrium position before stopping and turning back.
What is the coefficient of kinetic friction between the block and the table?

Homework Equations


F=uk*k*x
F=mg

The Attempt at a Solution


uk=mg/(k*x)
I don't know what x is, and even still I don't know if that is the correct way to do the equation.

Any help would be greatly appreciated.
 
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x is the compression, 4.4 cm. Or the distance of stretch.
It looks like an energy question to me. Something like this:
energy stored in compressed spring = work done against friction + energy stored in stretched spring
I don't see the energy of a spring formula in your list: E = 1/2k*x^2
 
I ended up solving this one. Thanks for replying though!
 

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