What is the coefficient of kinetic friction for a wood block on a spring?

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SUMMARY

The coefficient of kinetic friction (uk) for a wood block on a spring can be calculated using the formula uk = mg/(k*x), where m is the mass of the block (0.570 kg), k is the spring constant (180 N/m), and x is the distance of compression (4.4 cm). The energy stored in the compressed spring is equal to the work done against friction plus the energy stored in the stretched spring. The relevant energy formula is E = 1/2k*x^2, which is crucial for solving the problem accurately.

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Homework Statement


A 0.570-{\rm kg} wood block is firmly attached to a very light horizontal spring(k=180 N/m). It is noted that the block-spring system, when compressed 4.4 cm and released, stretches out 1.7 cm beyond the equilibrium position before stopping and turning back.
What is the coefficient of kinetic friction between the block and the table?

Homework Equations


F=uk*k*x
F=mg

The Attempt at a Solution


uk=mg/(k*x)
I don't know what x is, and even still I don't know if that is the correct way to do the equation.

Any help would be greatly appreciated.
 
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x is the compression, 4.4 cm. Or the distance of stretch.
It looks like an energy question to me. Something like this:
energy stored in compressed spring = work done against friction + energy stored in stretched spring
I don't see the energy of a spring formula in your list: E = 1/2k*x^2
 
I ended up solving this one. Thanks for replying though!
 

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