What is the Correct Setup for a Lorentz Transformation Matrix?

soothsayer
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Homework Statement


Show that the following is a Lorentz Transform:
\Lambda _{j}^{i}=\delta _{j}^{i}+v^iv_j\frac{\gamma -1}{v^2}
\Lambda _{j}^{0}=\gamma v_j , \Lambda _{0}^{0}=\gamma , \Lambda _{0}^{i}=\gamma v^i

where v^2 =\vec{v}\cdot \vec{v}, and \delta _{j}^{i} is the Kronecker Delta.

Homework Equations


\eta_{\mu\nu}=\eta_{\mu'\nu'}\Lambda_{\mu}^{\mu'} \Lambda_{\nu}^{\nu'}
\eta = \Lambda^T \eta \Lambda

The Attempt at a Solution


I know how to go about proving a transform is a Lorentz transform, based on my "relevant equations", but I'm having a hard time setting the \Lambda matrix up correctly. When I set up the matrix, I have terms in every cell, such as
\Lambda_{1}^{1}=1+v^1 v_1 \frac{\gamma -1}{v^2}
and
\Lambda_{1}^{2}=v^2 v_1 \frac{\gamma -1}{v^2}

and so on and so forth, but this feels wrong. I end up having to multiply two exceedingly complicated matrices along the way, which I know to be wrong (the professor hinted that excessive matrix multiplication was a sign you were doing the problem wrong.) How do I set things us? What I really want to know is, what is \Lambda_{j}^{i}? How do I handle the vector indices (vi, vj)?
 
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I think you should do this, let g_{\mu\nu}=\eta_{\mu'\nu'}\Lambda_{\mu}^{\mu'} \Lambda_{\nu}^{\nu'} then you sholud show that g_{\mu\nu}=\eta_{\mu\nu}. This you can do calculating for each case g_{00},g_{0k}\, and\, g_{kl} using
g_{\mu\nu}=\eta_{\mu'\nu'}\Lambda_{\mu}^{\mu'} \Lambda_{\nu}^{\nu'}=\eta_{00}\Lambda_{\nu}^{0}\Lambda_{\mu}^{0}+\eta_{ij}\Lambda_{\nu}^{i}\Lambda_{\mu}^{j}
=-\Lambda_{\nu}^{0}\Lambda_{\mu}^{0}+\delta_{ij}\Lambda_{\nu}^{i} \Lambda_{\mu}^{j}=-\Lambda_{\nu}^{0}\Lambda_{\mu}^{0}+\Lambda_{\nu}^i\Lambda_{\mu}^i
 
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Ok, that makes some sense to me. I'll give it a try, thank you!

The only part I couldn't follow is where you came up with the \delta_{ij} \Lambda_{\nu}^{i} \Lambda_{\mu}^{j}. Where did the delta come from? Sorry, I'm quite new at this sort of math.
 
soothsayer said:
The only part I couldn't follow is where you came up with the \delta_{ij} \Lambda_{\nu}^{i} \Lambda_{\mu}^{j}. Where did the delta come from? Sorry, I'm quite new at this sort of math.
assuming that latin indices take on values 1,2,3 while greek indices 0,1,2,3 then \eta_{ik}=\delta_{ik} while \eta_{00}=-1
 
Ah, right, thank you!
 
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