What is the Distance d in Snell's Law and the Pythagorean Theorem?

AI Thread Summary
To find the distance d in Snell's Law and the Pythagorean Theorem, the relationship n_asinΘ_a=n_bsinΘ_b is used alongside a^2+b^2=c^2. The angle Θ_b can be calculated using the formula sin^-1(1sin30/1.52) to determine the internal angle. The offset distance d of the emergent ray requires a geometric approach, specifically utilizing right-angled triangles. A clear diagram is essential for visualizing the problem and establishing the necessary relationships between the sides of the triangle. Without a diagram, the calculations and relationships may remain unclear.
h20proof
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In the following diagram find the distance d if a=4.0 mm, Θ=30°

n_asinΘ_a=n_bsinΘ_b: snells law
a^2+b^2=c^2: pythagorean theorem

I think I got the angle to the problem correct. I am not sure if this is correct. Is this correct Θ_b=sin^-1(1sin30/1.52)?
 

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That will give you the internal angle.

You are apparently required to find the offset distance, d, of the emergent ray.
 
thank you. How do you find it?
 
h20proof said:
thank you. How do you find it?
Using geometry. Specifically, the geometry of right-angled triangles.

You start by drawing a large clear diagram, and using a straight-edge to make all your straight lines look straight. Any lines you draw can be made into a side of a right-angled triangle.
 
okay, I still don't see it.
 
h20proof said:
okay, I still don't see it.
Where's your diagram?
 
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