What is the exponential decay equation for a bouncing ball?

In summary, the conversation discusses the concept of a bouncing ball and how its height decreases by 25% with each bounce. A table and formula are provided to demonstrate this concept and the use of LaTeX is suggested for displaying formulas.
  • #1
wolf1728
Gold Member
38
5
This is not a physics question.
Each time a ball bounces it will bounce to, let's say 75% of its previous height.
(I am not interested in the time, energy or velocity, of the ball.)
So if we drop it from 100 cm it will bounce back up to 75 cm, and on the next bounce it goes up to 56.25 cm and so on.
Here is a table for 6 bounces.
Starting height 100 cm
1st Bounce 75 cm
2nd Bounce 56.25 cm
3rd Bounce 42.1875 cm
4th Bounce 31.640625 cm
5th Bounce 23.73046875 cm
6th Bounce 17.797851563cm

Okay we can also say that on each bounce, the ball will lose 25% of its previous height.
So, basically, if we calculate this for every bounce, we can determine the height of any bounce.
Third Bounce Height = 100 -(100 *.25) - (75*.25) -(56.25*.25)

Finally, is there a much more compact formula then this one?
Thank you.
 
Mathematics news on Phys.org
  • #2
h0= 100
h1 = 0.75 h0
h2 = 0.75 h1 = (0.75)2 h0
h3 = 0.75 h2 = (0.75)3 h0
...
hn = ?
 
  • Like
Likes wolf1728
  • #3
kuruman said:
h0= 100
h1 = 0.75 h0
h2 = 0.75 h1 = (0.75)2 h0
h3 = 0.75 h2 = (0.75)3 h0
...
hn = ?
Thanks for the quick reply!
Just to help you out, the coding for superscripts is <sup>2</sup>
OR if you want to make the "squared" sign hold the "ALT" key and simultaneously type 0178 on the number key pad and you'll get ²
to get the "cubed" sign it's the "ALT" key plus 0179 and you get ³
 
  • #4
wolf1728 said:
Thanks for the quick reply!
Just to help you out, the coding for superscripts is <sup>2</sup>
OR if you want to make the "squared" sign hold the "ALT" key and simultaneously type 0178 on the number key pad and you'll get ²
to get the "cubed" sign it's the "ALT" key plus 0179 and you get ³

You can use Latex, which generally better:

https://www.physicsforums.com/help/latexhelp/

For example:

##h_n = (0.75^n) h_0##
 
  • #5
wolf1728 said:
Thanks for the quick reply!
Just to help you out, the coding for superscripts is <sup>2</sup>
OR if you want to make the "squared" sign hold the "ALT" key and simultaneously type 0178 on the number key pad and you'll get ²
to get the "cubed" sign it's the "ALT" key plus 0179 and you get ³
Thanks. I was too lazy to fuss with subscripts or LaTeX, nevertheless the message got across.
 
  • #6
kuruman said:
(0.75)2 h0

wolf1728 said:
Just to help you out, the coding for superscripts is <sup>2</sup>
Not at this site. The BBCode for exponents is [sup]exponent[/sup]; i.e., with brackets, not angle brackets. This is what @kuruman used.

wolf1728 said:
OR if you want to make the "squared" sign hold the "ALT" key and simultaneously type 0178 on the number key pad and you'll get ²
to get the "cubed" sign it's the "ALT" key plus 0179 and you get ³
Much too complicated and hard to remember, especially that you need to enter the numbers as octal, which is why you need to enter 0178 or 0179 instead of 178 or 179. As already advised, LaTeX works on this site, and is much nicer than BBCode or the extended ASCII codes for exponents of 2 and 3.

For tutorials for both BBCode and LaTeX, look under the INFO menu, under Help/How-to.
 
  • #7
Thanks for the alert Mark44.
I've had my own website for about 20 years and I guess I haven't kept up with the latest "fancy-schmancy" computer tricks.
(Heck, my computer runs on coal! LOL)
 

1. What is the meaning of the exponential decay equation for a bouncing ball?

The exponential decay equation for a bouncing ball is a mathematical model that describes the height of a ball as it bounces repeatedly on a flat surface. It takes into account the initial height of the ball, the gravitational constant, and the coefficient of restitution (a measure of how much energy is lost in each bounce).

2. How is the exponential decay equation derived for a bouncing ball?

The exponential decay equation for a bouncing ball is derived using the principles of conservation of energy and the laws of motion. It is based on the assumption that the ball bounces in a perfectly elastic manner, meaning that no energy is lost during each bounce. This allows for a simple exponential decay model to be used to describe the height of the ball over time.

3. What factors affect the value of the exponential decay constant in the equation for a bouncing ball?

The value of the exponential decay constant in the equation for a bouncing ball is affected by the coefficient of restitution, which determines how much energy is lost in each bounce, and the gravitational constant, which determines the acceleration due to gravity. Other factors that may affect the value of the constant include air resistance and the surface on which the ball is bouncing.

4. How accurate is the exponential decay equation for a bouncing ball?

The accuracy of the exponential decay equation for a bouncing ball depends on the assumptions made in its derivation and the conditions under which the ball is bouncing. In real-world scenarios, other factors such as air resistance and imperfections in the ball or surface may affect the accuracy of the equation. However, for idealized scenarios with perfectly elastic bounces, the equation can provide a good approximation of the ball's height over time.

5. Can the exponential decay equation for a bouncing ball be used for other objects besides a ball?

While the exponential decay equation was derived specifically for a bouncing ball, it can be applied to other objects that undergo repeated bounces with a constant coefficient of restitution. However, the equation may need to be modified for objects with different shapes or compositions. Additionally, factors such as air resistance may need to be taken into account for objects other than a ball.

Similar threads

  • General Math
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
3K
  • Mechanics
Replies
4
Views
897
Replies
14
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
7K
  • Introductory Physics Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
4K
  • Introductory Physics Homework Help
Replies
9
Views
4K
  • Introductory Physics Homework Help
Replies
3
Views
1K
Back
Top