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nahanksh
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Homework Statement
http://online.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?courses/phys211/oldexams/exam2/fa08/fig5a.gif
A frictionless ramp of mass 3m is initially at rest on a horizontal frictionless floor. A small box of mass m is placed at the top of the ramp and then released from rest. After the box is released, it slides down the ramp and onto the horizontal floor, where it is measured to have a speed v, having fallen a total distance h.
What is the speed v of the box after it has left the ramp?
http://online.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?courses/phys211/oldexams/exam2/fa08/fig5b.gif
Homework Equations
d(K.E.) = -d(P.E.)
The Attempt at a Solution
I don't quite get the situation here..(maybe poorly worded)
What's the meaning of the velocity of "pointing right" in the figure?
Anyway, when interpreting that as the same variable as velocity of the block,
i tried to do like the following:
Using the above equation,(Energy conservation)
0.5*m*v^2 + 0.5*(3m)*v^2 = mgh
Then the answer coming from this is not in the options...
What's wrong in my attempt?
Could someone help me out here, please?
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