What is the final temperate of the aluminum?

  • Thread starter Thread starter Dave25
  • Start date Start date
  • Tags Tags
    Aluminum Final
AI Thread Summary
To determine the final temperature of a 121 g piece of aluminum after adding 69.3 J of heat at an initial temperature of 22.5 C, the equation Q = mc(T - T1) is applicable. The specific heat of aluminum is necessary to complete the calculation. The user expressed confusion about the use of the heat value in the equation but received confirmation that their approach was correct. With the specific heat value, the final temperature can be accurately calculated. This discussion highlights the importance of understanding specific heat in thermal calculations.
Dave25
Messages
29
Reaction score
0

Homework Statement



Suppose 69.3 J of heat is added to a 121 g piece of aluminum at 22.5 C. What is the final temperate of the aluminum?

Homework Equations



Q = m c (T - T1) I think, but I am only given 1 temp.

The Attempt at a Solution



There are examples that are simialr in my book except they don't use a figure like 69.3 J. This is what is confusing me. If someone could tell me the equation I should use I would really appreciate it. Thanks.
 
Physics news on Phys.org
Try looking up the specific heat of aluminum. This is the last piece of information that you'll need to solve the problem.

Your equation is correct.
 
Got it! Thanks.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

How Hot Was the Campfire's Aluminum Can Before Cooling in Water?
Replies
2
Views
2K
Rate of Energy Transferred, Aluminum Pot
Replies
5
Views
2K
Find the final Celsius temperature of the aluminum and water
Replies
2
Views
2K
Change in temperature for a system with entropy change
Replies
4
Views
2K
How much heat in joules must be added to 0.841 kg of aluminu
Replies
4
Views
4K
Impact of container on final temperature of system
Replies
8
Views
2K
Calories Required to Raise the Temp of Aluminum
Replies
3
Views
2K
Density: Cube of Aluminum to Copper Sphere
Replies
3
Views
5K
Iron and Ice in Aluminum bucket of water
Replies
14
Views
2K
Entropy Change of Touching Blocks That Reach Equillibrium
Replies
7
Views
5K

Hot Threads

Recent Insights

Back
Top