What is the force on an electron traveling parallel to the wire

AI Thread Summary
Two parallel wires carrying opposite currents create a magnetic field that can be calculated using the formula B = μ₀I/2πr. The discussion involves calculating the magnetic field at specific distances from the wires and the force on an electron moving parallel and perpendicular to a wire. The Lorentz force equation F = qvB is applied to determine the force on the electron, with considerations for its direction using the right-hand rule. Participants clarify calculations and correct any errors, emphasizing the importance of understanding magnetic field direction and force application. The conversation highlights the need for accurate distance measurements and the correct application of physics principles.
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1. Two parallel wires 0.200 m apart carry currents in opposite directions of 5.00 A. Find the
magnetic field between the wires 0.0500 m from one of them and 0.150 m from the other.

2. A long straight wire carries a current of 100. A.
a. What is the force on an electron traveling parallel to the wire, in the opposite
direction to the current, at a speed of 2.50x106 m/s when it is 0.100 m from the
wire?

Attempt: F=qvB

b. Find the force on the electron under the above circumstances when it is traveling
perpendicular to the wire.
electronic charge 1.602x10-19 C
 
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Just writing the Lorentz Force law isn't really an attempt.

How would you think to approach it?
 


for the first one, do we just get the magnetic field total? This is what i did.

Btotal = B1 + B2
B1 = MoI/2IIr ---> [(1.26X10^-6)(5)/(6.28)(15)
B2 = MoI/2IIr ---> [(1.26x10^-6)(5)/(6.28)(0.05)

Is that right?

for the second one, I calculated magnetic field first. Then, used this equation:

F=qvb
Magnetic force faces the positive x direction, right? I am still kinda confused about the right hand rule

b. Magnetic force faces in the negative y direction?

please let me know if I am wrong about anything. Thanks !
 
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