What is the heat added to this monatomic ideal gas

AI Thread Summary
To determine the heat added to a monatomic ideal gas expanding at a constant pressure of 110 kPa from 0.75 m³ to 0.93 m³, the work done on the gas can be calculated using W = P∆V. The change in internal energy, ∆U, can be expressed as ∆U = (3/2)nR∆T, where n is the number of moles and R is the ideal gas constant. The heat added, Q, is then found using the equation Q = ∆U + W. The discussion highlights the need for assumptions regarding temperature change to accurately calculate ∆U. Understanding these relationships is crucial for solving the problem effectively.
Brit412
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Homework Statement


A monatomic ideal gas expands at a pressure of 110kPa and from a volume of 0.75m^3 to 0.93m^3. Find the amount of heat added to the gas.


Homework Equations


So what I did was:
W= P∆V
and I know ∆U= Q-W
so Q would equal ∆U+W, but how do you know what ∆U equals?


The Attempt at a Solution

 
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what are you assumptions? that will tell you what delta U is equal to.
 


If I assume that this is at a constant pressure ∆U= 3/2nR∆T?, but since W=P∆V=nR∆T then ∆U= 3/2W?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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