What Is the Kinetic Energy Equation for a Mass on a Double Pendulum?

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Homework Help Overview

The discussion revolves around the kinetic energy equation for a mass on a double pendulum, particularly in the context of a statics class and upcoming advanced dynamics studies. The original poster seeks to understand how to derive the kinetic energy based on the system's configuration and external torques.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to relate the kinetic energy to the angular velocities of the pendulum system and questions how to calculate these velocities. Some participants suggest alternative perspectives, while others express confusion about the relevance of certain comments.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the kinetic energy equation and the dynamics of the double pendulum. There is a lack of consensus, but some guidance on the relationship between angular velocities has been initiated.

Contextual Notes

The original poster mentions their background in calculus and upcoming coursework, indicating a desire to apply theoretical knowledge to a personal project. There is also a reference to specific equations and concepts from their studies, which may influence the discussion.

Axecutioner
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You can treat the cable as another rigid bar in this case, both massless. I just need the equation for the Kinetic Energy of the mass on the end.

Is there an equation for if the main bar is torqued at a given τ(t), and any other necessary information is given, to find the position of the mass on the end or the angles of the two bars at any given time?

I'm in a Statics class right now and will be taking advanced dynamics in the fall but I'd like to work on a personal project in the fall. Done through Calc 4 and Stokes Theorem if it matters.

Thanks
 
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Burn the thread. The ball will remain and will perform free fall. Then you will easily get your answer.
 
That doesn't help at all.

I know K = 1/2*I*w^2 but what would the omega be? Just both angular velocities added together?
 
Sorry, misunderstanding. Please delete this post.
 
Last edited:

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