What Is the Magnetic Force on a Single Electron?

AI Thread Summary
The discussion revolves around calculating the magnetic force on a single electron using the formula F = BIl. Initially, the user calculated the force as 0.64 but was confused about dividing by the number of electrons to find the correct answer. It was clarified that the provided value was the density of free electrons, not the total number. By calculating the volume of the wire and using the density, the correct number of electrons can be determined, leading to the correct answer. Ultimately, the correct approach involves using the density and volume to find the total number of electrons.
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Homework Statement


question - see image
attachment.php?attachmentid=45908&d=1333628221.png

Homework Equations


The Attempt at a Solution



so I use the equation F = BIl
F = 0.2 * 0.4 * 8 = 0.64
Surely I just divide it by the number of electrons (8*1028) to get the answer
BUT this does not give the correct answer.

The correct answer is D?
 

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jsmith613 said:
so I use the equation F = BIl
F = 0.2 * 0.4 * 8 = 0.64
Surely I just divide it by the number of electrons (8*1028) to get the answer
BUT this does not give the correct answer.

The correct answer is D?

Ah. That's not the number of free electrons, that's the density of free electrons.
 
gneill said:
Ah. That's not the number of free electrons, that's the density of free electrons.
so density / area = number/m
right?
 
Last edited:
jsmith613 said:
so density / area = number/m
right?

##\rho = \frac{n}{volume}##

If you calculate the volume of the wire you can find the total n.
 
gneill said:
##\rho = \frac{n}{volume}##

If you calculate the volume of the wire you can find the total n.

so n = density * volume
n = 8 * 1028 * 0.4 * 10-6

therefore answer = D

thanks
 
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