What is the measure of an isosceles triangle angle when given its base angles?

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The discussion centers on finding the measure of an angle in an isosceles triangle with given base angles. The base angles are represented as x and (146-x), leading to the equation x + (146-x) + ? = 180. Participants debate whether the angles can be unequal based on the value of x, with one user asserting that x must equal 34 for the triangle to hold true. Another user challenges the algebra and the correctness of the equation used to derive the angles. The conversation highlights the confusion surrounding the properties of isosceles triangles and the conditions for their angles.
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Homework Statement


Find x[/B]
bandicam 2016-08-12 22-16-18-190.jpg


Homework Equations


a+b+c=180
[/B]

The Attempt at a Solution


So RP=RQ, the base angles are x and (146-x), normally the base angles are the same but in this scenario they are different.
x+146-x+?=180
 
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Frank212 said:
normally the base angles are the same but in this scenario they are different.
How can you build a isosceles triangle with unequal base angles?
 
?=34
 
Frank212 said:

Homework Statement


Find x[/B]
View attachment 104589

Homework Equations


a+b+c=180
[/B]

The Attempt at a Solution


So RP=RQ, the base angles are x and (146-x), normally the base angles are the same but in this scenario they are different.
x+146-x+?=180

Why do you say that x and 146-x are different? Wouldn't that depend on the value of x?
 
I marked this solved
 
Frank212 said:
I marked this solved
What's your solution ?
 
SammyS said:
What's your solution ?
x+146-x+x=180
x+146=180
x=34,
180-34=146
146/2=73
x=73
 
Last edited:
Frank212 said:
x+146-x+x=180
x+146=180
x=73
Really? Check your algebra. Also, your equation is incorrect.
 
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