What is the minimum wavelength of x-rays produced by a 50 kV emf?

Click For Summary
SUMMARY

The minimum wavelength of x-rays produced by a 50 kV emf can be calculated using the formula λ = hc/(50 keV). This equation is derived from the principles of Bremsstrahlung radiation, where the energy of an electron is converted into a photon. The relationship indicates that as the voltage increases, the energy of the emitted x-rays also increases, resulting in a shorter wavelength. The formula accounts for the maximum photon energy scenario, acknowledging potential energy losses in practical applications.

PREREQUISITES
  • Understanding of electromagnetic radiation principles
  • Familiarity with the concept of Bremsstrahlung radiation
  • Knowledge of the relationship between voltage and photon energy
  • Basic grasp of quantum mechanics and photon behavior
NEXT STEPS
  • Study the derivation of the Bremsstrahlung radiation formula
  • Learn about the energy-momentum relationship in quantum mechanics
  • Explore the applications of x-ray production in medical imaging
  • Investigate the effects of voltage variations on x-ray wavelength
USEFUL FOR

Students in physics, radiology professionals, and anyone interested in the principles of x-ray production and electromagnetic radiation.

fluidistic
Gold Member
Messages
3,934
Reaction score
283

Homework Statement


An x-rays tube is connected to a 50 kV emf. Calculate the minimum wavelength that one can find in the radiation spectra that the tube produces.

Homework Equations


No idea! This is why I ask help here.

The Attempt at a Solution


Stuck at start. I've searched in google and wikipedia about calculating the wavelength of x-rays in function of the voltage across the emf, but I didn't find any formula.
So if you either know a page or a formula, feel free to share.Edit: Nevermind I find out in wikipedia about Bremsstrahlung. It gives me \lambda = \frac{hc}{50 k eV}.
 
Last edited:
Physics news on Phys.org
The theory is that the energy of one electron is transferred to one photon. There may be some loss of energy, so the theory actually gives the minimum wavelength (maximum photon energy) case.
Energy of electron = energy of photon
qV = hc/λ
 

Similar threads

X-ray production and ionization energy
  • · Replies 2 ·
Replies
2
Views
2K
Effect of Change of Potential difference applied to an X-Ray tube
  • · Replies 4 ·
Replies
4
Views
4K
Calculation of the least value of PD needed to produce x-rays
  • · Replies 11 ·
Replies
11
Views
2K
Stationary Target X-Ray Tubes - Energy
  • · Replies 1 ·
Replies
1
Views
1K
What Is the Minimum Potential Needed to Emit X-Ray Photons of 10^-10 Meters?
  • · Replies 4 ·
Replies
4
Views
2K
Undergrad What travels faster: visible light in water or X-rays in liquid mercury?
  • · Replies 6 ·
Replies
6
Views
3K
X ray crystallography - interpreting my graph
  • · Replies 1 ·
Replies
1
Views
2K
What is the potential for extremity doses in this X-ray exposure incident?
  • · Replies 3 ·
Replies
3
Views
2K
Undergrad Why Bremsstrahlung <20keV for Tungsten?
  • · Replies 17 ·
Replies
17
Views
4K
Wavelength of Sound: Solve Using X & Y
  • · Replies 6 ·
Replies
6
Views
2K