What is the net torque on the pulley about the axle

AI Thread Summary
The net torque on the pulley is calculated using the formula torque = r(Ft), where Ft is the force applied perpendicular to the radius. In this case, the forces T1 and T2 are 18N and 34N, respectively. The discussion emphasizes calculating the torque for each force individually, considering their directions (clockwise or counterclockwise). It is noted that when the angle is 90 degrees, the sine component simplifies the calculation. Understanding these principles allows for the correct determination of the net torque on the pulley.
aligass2004
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Homework Statement



What is the net torque on the pulley about the axle if T1 = 18N and T2 = 34N?
http://i241.photobucket.com/albums/ff4/alg5045/p13-11.gif

Homework Equations





The Attempt at a Solution



Torque is really confusing me. I have no ideas as to how to start this problem.
 
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You're going to have to show some work, but to "push" you along... could you get started if there were only 1 force?
 
I know that torque = r(Ft), but I don't know if that's the right equation to use.
 
I'm guessing that Ft is the force that is perpendicular to the radius. Is that what you mean? If so, that is the right equation.

To give a longer answer than you might want,
Torque = force x radius x sine of the angle between the force and the radius.
In many cases, the angle is 90 degrees (it certainly is in your picture) and sin(90) = 1, so torque = force x radius in those cases.

So, now can you calculate the two torques, ONE AT A TIME, including whether it goes clockwise (CW) or counterclockwise (CCW)?
 
I figured it out before looking at your last post. Thanks though!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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