Hello, I am having difficulty answering the following problem: consider two antennas, separated by X meters that radiate in phase at f. A reciever placed 150 m from both antennas measures an intensity I_o. The reciever is moved so that it is 1.8 m closer to one antenna than ot the other. What is the phase difference between the two radio waves produced by the path difference? okay. so I know i want to use the formula: phase diff = 2pi/lamda*(r_2 - r_1) i was able to calculate lamda, however I'm not sure about the path difference. Would that be my 1.8 m?? or is there trig involved here in order to figure out r_2 - r_1 ??