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sghaussi

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consider two antennas, separated by X meters that radiate in phase at f. A reciever placed 150 m from both antennas measures an intensity I_o. The reciever is moved so that it is 1.8 m closer to one antenna than ot the other.

What is the phase difference between the two radio waves produced by the path difference?

okay. so I know i want to use the formula: phase diff = 2pi/lamda*(r_2 - r_1)

i was able to calculate lamda, however I'm not sure about the path difference. Would that be my 1.8 m?? or is there trig involved here in order to figure out r_2 - r_1 ??