What is the Probability of Double Bulb Failure within a Given Time Period?

CaptainEvil
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Homework Statement



a) A lamp has two bulbs of a type with an average lifetime of 1000 hours. Assuming that we can modelthe probability of failure of these bulbs by an exponential density function \mu = 1000, find the probability that both of the lamps bulbs will fail within 100 hours.

b) Another lamp has just one bulb of the same type as in part (a). if one bulb burns out and is replaced by a bulb of the same time, find the probability that the two bulbs fail within a total of 1000 hours.

Homework Equations





The Attempt at a Solution



I'm pretty sure \mu = double integral on a region D of xf(x,y)dA but I don't know what my region or f(x,y) would be.
 
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1) Think about the support for exponential.
2) Why do you think it's x*f(x,y)?
 
formula's from my textbook give

\mu1 = double integral over the region of x*f(x,y)
and same for \mu2 with y*f(x,y)

It's the same as solving for mass and centre of mass over a region with double integrals
 
Well you want P(bulb1 fails and bulb2 fails) they are independent, so can you rewrite that?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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