What is the ratio of radii for the two species X+ and X2+?

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Homework Help Overview

The problem involves determining the ratio of the radii of circular paths for two ionized species, X+ and X2+, in a magnetic field after being accelerated through the same electric potential. The context includes considerations of mass, charge, and the effects of acceleration on velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relevant equation for the radius of the path and consider how to derive the ratio of the radii. There is confusion regarding the velocities of the two species and how they relate to their charges and masses.

Discussion Status

Some participants have attempted to derive the ratio of the radii by manipulating the equations for each species. There is recognition of the need to consider differences in velocity due to the differing charges, and some guidance has been offered regarding the cancellation of terms in the equations.

Contextual Notes

Participants note that the teacher's solution suggests a different ratio than what some have calculated, leading to further questioning about the assumptions made regarding velocity and acceleration. There is an acknowledgment that the mass of the two species is effectively the same, but the impact of charge on acceleration is under discussion.

KatieD
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Homework Statement



The ion source is a spectrometer produces both singly and doubly ionized species, X+ and X2+. The difference in mass between these species is too small to be detected. Both species are accelerated through the same electric potential difference, and both experience the same magnetic field, which causes them to move on circular paths. The radius of the path for the species X+ is r1 while the radius for species X2+ is r2. Find the ratio r1/r2 of the radii.

So this means:
m1=m2
V1=V2
B1=B2


Homework Equations


r=mv/qV


The Attempt at a Solution


We know that the charge of the X2+ is twice the X. I am just so confused about where to go from here. My teacher has written out the solution but it still makes no sense.

Please help :(

Katie
 
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You just about have it with your equation don't you?

Consider the equation for each particle.

Now take the ratio of the equations.

If the masses are virtually identical, the acceleration through the electrical potential and hence the velocities are also the same then aren't they?

By the time you get through canceling things out it looks to me like you can determine r1/r2 by inspection.
 
so here's where i am at:

r1=mv/qB
r2=mv/2qB

I then divide r1 and r2 getting
((m1v1)/(qB))/((m2v2)/(2qB))

then with canceling out I get r1/r2=2

I am confused, the teachers notes say its the square root of 2, I am not sure where this comes in
 
KatieD said:
so here's where i am at:

r1=mv/qB
r2=mv/2qB

I then divide r1 and r2 getting
((m1v1)/(qB))/((m2v2)/(2qB))

then with canceling out I get r1/r2=2

I am confused, the teachers notes say its the square root of 2, I am not sure where this comes in

Oops. Sorry. The acceleration through the electrical potential will result in a velocity that is not identical. It will be different how?
 
EPE= Vq
so if the force goes up... and the mass is the same the acceleration will have to go up with the second one by 2 right?
 
KatieD said:
EPE= Vq
so if the force goes up... and the mass is the same the acceleration will have to go up with the second one by 2 right?

I think they want you to accelerate that from rest. So ...

W = q*ΔV = 1/2*m*v2

Which means that the ratio of v2 = 2:1, since v2 is proportional to the charge.
 

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