What is the Rotation Tensor Matrix for Rotation About e1+e2 Axis?

AI Thread Summary
The discussion focuses on deriving the rotation tensor matrix for a rotation by angle θ about the axis aligned with e1+e2. Participants explore the idea that the rotation primarily affects the e3 axis, leading to a matrix that may appear to have zero components except for a complex value in R33. One user suggests a method of rotating e1+e2 onto e1, applying the rotation, and then returning to the original axis. They propose a matrix structure that includes sine and cosine functions, indicating that the rotation tensor should reflect these trigonometric components rather than simple integers. The conversation highlights the need for careful consideration of the rotation's impact on the matrix's determinant, which is noted to be -1.
samee
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Homework Statement



Write the matrix of a rotation tensor corresponding to the rotation by angle θ about an axis aligned with e1+e2

Homework Equations



I know that the matrix for a rotation tensor about e3 is;

cosθ -sinθ 0
sinθ cosθ 0
0 0 0

The Attempt at a Solution



I assume that the rotation would be changing only on the e3 axis because the axis are aligned with e1+e2, right? So the matrix will be all zero with the R33 component being some complicated rotated value?
 
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hi samee! :smile:

(try using the X2 button just above the Reply box :wink:)

how about rotating e1+e2 onto e1, then rotating through θ, then rotating e1 back again onto e1 +e2 ? :wink:
 
Okay! I had some new revelations.

I know that (R-I)u=0 where R is the rotation tensor, I is Identity and u is some vector, here it's e1+e3.

So, this equation will be true if the R matrix is;

0 1 0
1 0 0
0 0 1

BUT! I think it needs to be in sinθ and cosθ instead of 1... right?

Also- thanks for the tip on the X2 ^_^
 
samee said:
0 1 0
1 0 0
0 0 1

erm :redface:

the determinant of that is -1 :biggrin:
 
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