What is the speed of a BB fired from a spring-compressed BB gun?

  • Thread starter Thread starter pinkyjoshi65
  • Start date Start date
  • Tags Tags
    Ball Spring
AI Thread Summary
A BB gun fires an 8.24-g projectile using a spring with a stiffness of 2.88 × 10^3 N/m and a barrel length of 15.1 cm. The force exerted by the spring when compressed 16 mm is calculated to be 4.74 N. The kinetic energy of the BB as it exits the barrel is derived from the potential energy of the spring minus the work done against friction. The relevant equation to find the speed of the BB involves the work-energy theorem, incorporating the mass of the BB, spring constant, and frictional force. This analysis highlights the interplay between potential energy and friction in determining the BB's exit speed.
pinkyjoshi65
Messages
260
Reaction score
0
A BB gun fires a 8.24-g projectile by using a compressed spring (k = 2.88 × 103 N/m) and a 15.1 cm long barrel. As the disc travels through the barrel, it experiences a constant frictional force of 0.125 N. If the spring is compressed 16 mm, what is the speed of the BB as it leaves the gun?


So now we know that the Force is kx= 2.88*103*0.016= 4.74N

so..we use F=ma and find a.

then i got stuck..
 
Physics news on Phys.org
Gain in kinetic energy during the course of the motion of the disc, from the instant it was fired till the point when it leaves the barrel; is the sum of the potential energy of the compressed spring and the work done by the barrel(which is negative) If v is required, use:

\frac{1}{2} mv^{2} = \frac{1}{2} kx^{2} - Fs

F is the constant retarding force applied by the barrel, and s is the length of the barrel.
The above equation is just the work energy theorem.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top