What is the torque needed to open a 2000kg door?

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To open a 2000kg door that is 3m wide and 4m high, the torque required can be calculated using the formula torque = force x distance from the hinge. Assuming negligible friction, the torque acting through the center of gravity is 2000kg multiplied by 1.5m (half the width) and the acceleration due to gravity (9.81m/s²). If the goal is to open the door in ten seconds, the angular acceleration can be determined using the relationship between torque, moment of inertia, and angular acceleration. The discussion emphasizes the importance of specifying the desired speed of the door's opening to calculate the necessary torque accurately. Understanding these principles will aid in determining the angular velocity and acceleration needed for the door's movement.
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My door is 2000kg, it is 3m wide, 4m high and is on a hinge. for the moment i am saying that friction is negligable. How much torque is required to open my door. I have already said that the torque needed to open the door is acting through the C.O.G so it is 2000(1.5)(9.81), i don't know if that is correct though, please help :) If I can find this then I can find out the angular velocity and acceleration
 
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If friction is negligible and the door hinges are perfectly aligned, then any amount of torque will open the door.

How fast do you want the door to open?
 
want door to open in ten seconds.
 
You could apply the angular equal of Newton's laws for linear motion:

F = ma
torque = moment of inertia X angular acceleration
angular acceleration = change in angle / change in time.

Let me know if you need any help with this.
 

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