What is the velocity of an electron in a benzene molecule?

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The discussion centers on calculating the velocity of an electron in a benzene molecule, approximating it as an electron confined to a hoop. The radius of the benzene molecule is given as 5x10^-10 m, and the lowest allowed angular momentum is specified as h/2π. Participants express confusion regarding the variables and equations needed to solve the problem, particularly the interpretation of symbols in the provided materials. Clarification is made that the symbol in question is pi, not n, which alleviates some confusion. Overall, the conversation highlights the challenges faced in understanding the problem due to inadequate resources.
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Homework Statement


An electron in a benzene molecule makes a reasonable approximation to an electron
confined to a hoop. If the radius of the benzene molecule is about 5x10-10 m, and the
electron has the lowest allowed angular momentum of h/2π, what is the velocity of the
electron? (You may wish to recall the electron mass is 9x10-31 kg, and angular
momentum is L = rp = rmv.)


Homework Equations


I'm not entirely sure.


The Attempt at a Solution


I'm in a really poorly run workshop based class, so we have no textbook and the packets we were given are completely not at all helpful here.
 
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The two equations to use are in the problem.
 
What do you use for n though?
 
Where do you see n?
 
"angular momentum of h/2π"
 
Anochaa said:
What do you use for n though?

Are you sure that is an n? I believe it is a pi.
 
Oooh, my bad. Sorry! That completely threw me off - it looks like an n in the PDF. Now I just feel dumb, haha.
 
It definitely is pi.
 
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