What is the work done by weight on a crate being pushed up an inclined surface?

AI Thread Summary
To calculate the work done by the weight on a 300 kg crate pushed up a 30-degree incline, focus on the gravitational force acting on the crate. The work done by the weight is determined using the formula for work, which is the force of gravity (mg) multiplied by the vertical distance moved. Since the horizontal force and other details are not needed for this specific calculation, they can be disregarded. The key takeaway is that the work done by the weight is straightforward and can be computed directly from the weight and the vertical displacement. This highlights the importance of isolating relevant information in physics problems.
shaunanana
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Homework Statement



a 300 kg crate is on a rough surface inclined at 30 degrees. A constant force P=2400 N is applied horizontally to the crate. The force pushes the crate a distance of 3.0 m up the incline, in a time interval of 9.0 s, and the velocity changes from v1=0.7 m/s and v2=2.9 m/s. What is the work done by the weight?


Homework Equations



WD=F.d

The Attempt at a Solution


i have found the parallel components:
Fnet=Psin(theta) -mgsin(theta)
Psin(theta)-mgsin(theta)=ma
and the perpendicular components:
Fnet=Fn-mg
Fn=mg
I'm not 100% sure any of this is correct, and now I don't know where to go with it
 
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Welcome to PF!

Hi shaunanana! Welcome to PF! :smile:

(have a theta: θ and try using the X2 tag just above the Reply box :wink:)

You're only asked for the work done by the weight (the mg force), so most of the information in the question is unnecessary.

And work done = force "dot" distance.

So work done by the weight = … ? :smile:​
 
Oh wow, that's so simple...maybe I should stop trying to do my homework so late at night!

Thank you! :)
 
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