What magnitude charge creates a 4.17 N/C electric field at 9.78 m?

AI Thread Summary
To determine the magnitude of charge that creates a 4.17 N/C electric field at a distance of 9.78 m, the formula E = (k * Q) / r^2 is used, leading to a calculated charge of 4.43 x 10^10 C. A participant initially used the wrong constant (K = 9 x 10^-9) due to confusion with units, which was clarified in the discussion. Another example was presented involving an electric field of 199400 N/C at 4.1 cm, resulting in a charge of 3.72 x 10^-8 C, indicating a negative charge since the field points toward the object. The conversation highlights the importance of unit consistency and understanding charge characteristics based on electric field direction. Overall, the thread emphasizes solving electric field problems accurately while addressing common calculation errors.
BuBbLeS01
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Simple electric field problem...

Homework Statement


What magnitude charge creates a 4.17 N/C electric field at a point 9.78 m away?


Homework Equations





The Attempt at a Solution


E = (k * Q) / r^2
Q = (E * r^2) / K = 4.43 x 10^10 C
Why isn't that right?
 
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Check your math. I don't get the same answer with the expression you used.
 
oh shoot I was using K = 9 x 10^-9 because everything is in nC so that's what I did...thanks!
 
Is this question not asking the same thing?

The electric field 4.1 cm from a small object points toward the object with a strength of 199400 N/C. What is the object's charge?

q = 3.72 x 10^-8 C
 
BuBbLeS01 said:
Is this question not asking the same thing?

The electric field 4.1 cm from a small object points toward the object with a strength of 199400 N/C. What is the object's charge?

q = 3.72 x 10^-8 C

If the field is pointing towards the charge, what does that tell you about the charge?
 
its negative
 
Right. I don't see anything wrong with your calculation otherwise.
 
thanks so much!
 
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