What mass would be required to overcome static friction?

AI Thread Summary
To overcome static friction for a 1.53 x 10^3 g block of wood on a wood table with a coefficient of static friction of 0.40, the required force can be calculated using the formula: force = coefficient of static friction multiplied by mass. The discussion clarifies that mass alone does not overcome friction; rather, it is the force exerted by an additional mass that must exceed the frictional force. The frictional force in this scenario is 0.40 times the weight of the block. A system involving a hanging mass connected by a pulley is suggested to effectively demonstrate this principle. Understanding the relationship between mass and force is crucial for solving the problem.
Amber3046
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Homework Statement


The coefficient of static friction for wood on wood is 0.40, what mass would be required to overcome static friction of a 1.53 x 10^3 g block of wood on a wood table?


Homework Equations


I have absolutely no idea.


The Attempt at a Solution


I don't know.
Thanks for your help.
 
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Amber3046 said:

Homework Statement


The coefficient of static friction for wood on wood is 0.40, what mass would be required to overcome static friction of a 1.53 x 10^3 g block of wood on a wood table?


Homework Equations


I have absolutely no idea.


The Attempt at a Solution


I don't know.
Thanks for your help.
Perhaps the problem is that you are asking the wrong question. Mass will not "overcome friction". I presume you mean "force". Well, the definition of "coefficient of static friction" is "force required to move divided by mass" so the force you want is the coefficient of static friction multiplied by the mass.
 
Are you talking about a system where a block of wood is on a table and it is attached to a mass (through a pulley) which is hanging over the table? Because if so, what's needed is the mass which satisfies this equation:

1.53*10^3g * .4 < mg
(Friction Force) (Weight of mass)

p.s. I assume the g you used was grams?
 
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