What Type of Mirror Creates an Inverted, Real Image Half the Object's Size?

AI Thread Summary
To determine the type of mirror that creates an inverted, real image half the size of the object, the mirror formula 1/p + 1/i = 1/f is used, where p is the object distance and i is the image distance. The magnification equation, Ho/Hi = magnification, is also relevant, with Ho being the object height and Hi the image height. The discussion highlights the importance of converting the image characteristics into equations to solve the problem. Participants express confusion about setting up the equations but eventually find clarity through guidance. Understanding these principles is essential for solving similar optics problems.
Phower Power
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An object is placed 11 cm from a certain mirror. The image is half the height of the object, inverted, and real.


1/p+1/i=1/f



? Clueless because I don't know how to set up the equation int his kind of situation.
 
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Welcome to PF!

Hi Phower Power! Welcome to PF! :smile:
Phower Power said:
… I don't know how to set up the equation int his kind of situation.

I don't get it …

I assume you do know how to set it up in some other situation? :confused:

Just do the same, and convert "The image is half the height of the object, inverted, and real" into an equation also.
 
do you know the equation for magnification?
 
Nm, I got it! =)

Ho/Hi = magnification

Then I plug it in! Thank you for the clues
 

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