What weight is needed to keep a relief valve closed at 10 psi on a large vessel?

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To keep a relief valve closed at 10 psi on a large vessel, a pressure of 9.5 psi is required to counteract the valve's lift pressure of 0.5 psi. The calculation involves using the formula F = P*A, which results in a force of approximately 1075 lbs needed to maintain closure. The large area of the valve, approximately 113 square inches, significantly contributes to the force calculation. Despite initial doubts about needing such a high weight, the calculations confirm that this weight is necessary due to the pressure acting on the valve's area. Understanding these principles is crucial for safely managing pressure in large vessels.
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I have a large vessel that I would like to add a 10 psi purge to. There is a relief valve on it that is set to lift at 0.5 psi (essentially a flat circular plate 1 ft in diameter), so I am simply looking to keep this closed so that I can build up 10 psi inside the tank (don't worry, the tnak is rated for that pressure). Trying to figure out how much weight I'd need to do this, but doing the calc gives me a circular area of ~113 square inches, which would then provide a force of (113)(10) = 1130 lbf. I highly doubt I need 1130 pounds to hold this closed, so I must be missing something obvious here. Any insight would be greatly appreciated. Thanks
 
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Hi,

You need a pressure of 9.5psi to keep the valve shut (difference in pressure). Using F = P*A and W = F/g I get a weight of around 1075lbs. Seems a lot but it's quite a straight forward calculation - you have a large area that the pressure is acting on.
 
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