What's the Drift Velocity in a Copper Wire Carrying 0.50A?

AI Thread Summary
The discussion revolves around calculating the drift velocity of electrons in a copper wire carrying a current of 0.50A and determining the number of conducting electrons in a 10.0cm length of the wire. The user attempts to apply the formula v = I/(n * A * e) but arrives at an incorrect answer. Participants suggest reviewing the formulas and clarify the variables involved, emphasizing the importance of understanding the derivation of the equations used. The conversation highlights the need for a deeper comprehension of the concepts behind the calculations. Assistance is sought for clarification on the calculations and the meaning of specific variables.
hoyy1kolko
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Homework Statement


A copper wire of diameter 2.00mm carries a current of 0.50A.The number of conducting electrons per metre cube of copper is 8.00 x 10^28.
a)Calculate the drift velocity of the conducting electrons.
b)What is the number of conducting electrons in 10.0cm length of the wire


Homework Equations


I=nave
v=I/nae


The Attempt at a Solution


a) I=nave
v=I/nae
= 0.50/(8.00x10^25)(1x10^-3)(1.6x10^-19)
=3.9 x 10^-5 ms^-1
b)I=nave
n=I/ave
=0.50/(1x10^-3)(3.9x10^-5 )(1.6x10^19)
=8.0x 10^-3

The answer that i get is wrong.i don't know why.I need help and explanation.Is it need to derivate the formula then calculate?Thank you.
 
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What formula did you use to calculate a?
 
i don't know how to calculate a.I need help.
 
hoyy1kolko said:
i don't know how to calculate a.I need help.
We help those who help themselves. What does a represent? Look at the same place where you got the equation for the drift velocity.
 
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