When calculating the shear stress, what should the area be?

AI Thread Summary
When calculating shear stress, the area used can be either πr² or (π/4)d², depending on whether the radius or diameter is provided. The confusion arises when the diameter is given, leading to the area being calculated as (π/4)d², which simplifies to π(r²) when using the radius. The shear stress formula remains V/A, where A is the appropriate cross-sectional area. Understanding the relationship between radius and diameter clarifies the correct area to use. This distinction is crucial for accurate shear stress calculations in problems involving circular rods.
sunsee
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Homework Statement



I'm looking at some problems and solutions to them, and when they calculate shear stress instead of having the area of the thing be pi*r^2, there is usually a (pi/4)*r^2.

Homework Equations



Shear Stress = V/A

The Attempt at a Solution



I don't understand where they get the 1/4 in the denominator.
 
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You might want to review how shear stress is calculated. Your formula is not the usual one.
 
SteamKing said:
You might want to review how shear stress is calculated. Your formula is not the usual one.
I'm using and reading the chapter of shear stress in the book. That is what it tells me that shear stress is... Unless, I'm missing something.
 
The cross section area of a circular rod is (pi)(r^2) OR (pi)(d^2)/4
 
PhanthomJay said:
The cross section area of a circular rod is (pi)(r^2) OR (pi)(d^2)/4

Yeah, I figured it out. They gave the diameter in the problem so it was pi (d/2)^2. which is pi*(d^2)/4. I was stumped, but luckily i understand.

THANKS!
 

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