When Will a Sealed Tin Can Burst Due to Heating?

AI Thread Summary
The discussion centers on determining the temperature at which a sealed tin can will burst when heated, given initial conditions of pressure and temperature. The ideal gas law is referenced, but confusion arises regarding the application of constant volume and the resulting temperature calculations. One participant calculates a temperature of 459.5°C, while the expected solution is 483°C, prompting questions about the assumptions made in the calculations. Additionally, the impact of using an air compressor to increase pressure is questioned, suggesting that the temperature before bursting may differ due to changes in gas behavior. The conversation highlights the complexities of applying gas laws in real-world scenarios.
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Homework Statement



Air inside a sealed tin can is initially at a pressure of 200 kPa and temperature of 20 ◦C. The tin can is
known to burst at a pressure of 500 kPa. If the pressure is raised through heating, at what temperature will
it burst?
If you used an air compressor to pump up the can to high pressure, would the temperature before bursting
be the same? If not, why not?

Homework Equations


Pv=RT
P1/T1=P2/T2



The Attempt at a Solution



I'm confused. Why can't I just use the perfect gas law with constant volume to solve for the second temperature?

I get a result of 459.5degrees but solutions state that the answer should be 483 degrees.
 
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I aslo get 459.5C.
Were you dealing with a state equation different than the ideal gas law, like van der Waals?
Or maybe the can is supposed to expand.
 
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