Where Can I Find a Pressure-Temperature Phase Diagram for Pure Methanol?

AI Thread Summary
A user is seeking a pressure-temperature phase diagram specifically for pure methanol, expressing frustration with existing search results that only show diagrams for methanol mixtures. The user emphasizes that the diagrams found on Google do not meet their needs as they include various solvent combinations. There is a mention of Wolfram Alpha's diagram, which also does not provide the desired information. The discussion highlights the difficulty in locating accurate resources for pure methanol phase diagrams. The need for precise data on pure methanol is underscored.
Chemist20
Messages
80
Reaction score
0
PLEASE! I need to find a pressure-temperature phase diagram por PURE methanol!

it's driving me mad...
 
Physics news on Phys.org
When I put "methanol phase diagram" into Google I get diagrams on the top of the very first page of results. Something wrong with them?
 
Borek said:
When I put "methanol phase diagram" into Google I get diagrams on the top of the very first page of results. Something wrong with them?

Yes.. they aren't of pure methanol! they are mixtures of methanol with various solvents... :-(
 
And the one shown by wolfram alpha?
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...

Similar threads

Back
Top