Why Does Electrical Work Cause Changes in the Internal Energy of a System?

Click For Summary
SUMMARY

The discussion centers on the relationship between electrical work and changes in internal energy within a galvanic cell, as described by the first law of thermodynamics: $$ dU = dQ + dW' $$, where W' represents the electrical work done by the cell. It is established that in galvanic cells, electrical work is negative, indicating that the system does work on the surroundings, which results in a decrease in internal energy. The internal energy is defined as the sum of microscopic kinetic and potential energies, and the connection between electrical work and internal energy is clarified through the analogy of capacitors, where decreased charge correlates with decreased internal energy.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with galvanic cells and their operation
  • Knowledge of electrical work and potential difference
  • Basic concepts of internal energy in thermodynamics
NEXT STEPS
  • Study the first law of thermodynamics in detail
  • Explore the mechanics of galvanic cells and their energy transformations
  • Investigate the relationship between electrical work and internal energy changes
  • Learn about capacitors and their role in energy storage and transfer
USEFUL FOR

This discussion is beneficial for students and professionals in physics, chemistry, and engineering, particularly those interested in thermodynamics, electrochemistry, and energy systems.

Dario56
Messages
289
Reaction score
48
TL;DR
What does work done by electric field have to do with internal energy of the system? Why does electrical work cause changes in internal energy of the system?
If we look at system at constant temperature and volume which is galvanic cell, first law of thermodynamics states: $$ dU = dQ + dW' $$

Where W' is electrical work done by galvanic cell and Q is heat exchanged with surroundings.

As far as I know electrical work is work done by electric field when charge moves between certain potential difference. In galvanic cell, potential difference exists between two electrodes.

Internal energy is sum of total microscopic kinetic energy of all molecules and atoms and their potential energy of interaction (energy stored in intermolecular and chemical bonds).

What does work done by electric field have to do with internal energy of the system? Why does electrical work cause changes in internal energy of the system?

In galvanic cells, electrical work is negative as work is done by the system and from the first law it tends to decrease internal energy of the system.

I can't really see the connection between work done by electric field in the galvanic cell and sum of microscopic kinetic energy and microscopic potential energy of interaction.
 
Engineering news on Phys.org
Instead of chemical buttery let us see capacitor or condenser. Accumulated charges decrease by doing works in circuit and come back to opposite plate. Thus decreased charge means decreased internal energy. Though I am not well aware of chemistry I assume similar process is going in battery.
 

Similar threads

Replies
4
Views
3K
  • · Replies 53 ·
2
Replies
53
Views
5K
Replies
5
Views
662
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
15
Views
2K
  • · Replies 77 ·
3
Replies
77
Views
5K