Why Does Mass Positioning Affect Weight Discrepancies in Suspended Systems?

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Mass positioning affects weight discrepancies in suspended systems due to the principles of torque and leverage. When a mass is placed closer to the suspension point (X), the effective lever arm (r) decreases, resulting in reduced torque and perceived weight at that point. Conversely, moving the mass further away increases the lever arm, thereby increasing torque and the weight felt at the suspension point. The relationship between torque (τ), distance (r), and force (F) is crucial, as τ = r × F, illustrating how changes in distance impact the overall torque. Understanding these dynamics is essential for analyzing forces in suspended systems.
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A ruler is suspended from point x. When a mass is put at point y the mass at x is heavier than when it is at point p.
x-------------------p------------------------y
------------------------------------------------
Why is it that when the mass is moved closer to x the mass at x decreases?
 
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do you mean force?
 
I did not understand the question properly.
You mention that the ruler is suspended from the Point X which is the leftmost point then what effect will the mass have when it is put at the suspension point.

Just to put it into perspective.
Note
\tau =rXF
So at X the value of r is nil.
 
Last edited:
Sorry Tau=rXf
 
i.mehrzad said:
I did not understand the question properly.
You mention that the ruler is suspended from the Point X which is the leftmost point then what effect will the mass have when it is put at the suspension point.

Just to put it into perspective.
Note
\tau =rXF
So at X the value of r is nil.

yes which means the force at y is zero but the force at x is max
 
Thanks for the help but what I really wanted to know was why t=r x f. I can understand that the torque increases when the force is increased but why is it that when r increases the torque increases?
 
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